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x^2=40.96
We move all terms to the left:
x^2-(40.96)=0
We add all the numbers together, and all the variables
x^2-40.96=0
a = 1; b = 0; c = -40.96;
Δ = b2-4ac
Δ = 02-4·1·(-40.96)
Δ = 163.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{163.84}}{2*1}=\frac{0-\sqrt{163.84}}{2} =-\frac{\sqrt{}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{163.84}}{2*1}=\frac{0+\sqrt{163.84}}{2} =\frac{\sqrt{}}{2} $
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